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4x^2-37x^2+9=0
We add all the numbers together, and all the variables
-33x^2+9=0
a = -33; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-33)·9
Δ = 1188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1188}=\sqrt{36*33}=\sqrt{36}*\sqrt{33}=6\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{33}}{2*-33}=\frac{0-6\sqrt{33}}{-66} =-\frac{6\sqrt{33}}{-66} =-\frac{\sqrt{33}}{-11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{33}}{2*-33}=\frac{0+6\sqrt{33}}{-66} =\frac{6\sqrt{33}}{-66} =\frac{\sqrt{33}}{-11} $
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